Assign values based on two tresholds in pandas

Assign values based on two tresholds in pandas

Problem Description:

I have a pandas Dataframe named df and it has a column named logvalues.
I want to create a new column, violatedInstances based on these log values.

If Max >= logvalue >= Min assign 0 (Not violated)
If logvalue > Max or logvalue < Min assign 1 (Violated)

#create DataFrame
df_x = pd.DataFrame({'logvalue': ['20', '20.5', '18.5', '2', '10'],
                     'ID': ['1', '2', '3', '4', '5']})


Max = 20
min = 15

Output should look like below.

Sorry for asking this simple question. I tried several methods but nothing worked.
How can I do this in pandas?

Solution – 1

Your logvalue type is string so you’ll have to convert to float:

df_x['violatedInstances'] = df_x['logvalue'].astype(float).apply(lambda x: 1 if (x > Max or x < Min) else 0)

Solution – 2

cond1 = pd.to_numeric(df_x['logvalue']).gt(20)
cond2 = pd.to_numeric(df_x['logvalue']).lt(15)
df_x.assign(violatedInstances= (cond1 | cond2).astype('int'))

result:

logvalue    ID  violatedInstances
0   20      1   0
1   20.5    2   1
2   18.5    3   0
3   2       4   1
4   10      5   1

Solution – 3

First I would convert logvalue to a float so you can perform comparisons

df_x['logvalue'] = df_x['logvalue'].astype('float')

Then you can use numpy as such:

import numpy as np
df_x['violatedInstances'] = np.where(((df_x['logvalue'] > Max) | (df_x['logvalue'] < Min)), 1, 0)

which outputs: