# I'm getting an "Execution Timed Out" error?

## I'm getting an "Execution Timed Out" error?

Contents

Problem Description:

I’m trying to improve my algorithm skills. When I run my code, I get an "Execution Timed Out" error.

# Pseudocode

``````[This is writen in pseudocode]
if(number is even) number = number / 2
if(number is odd) number = 3*number + 1
``````

# My Code

``````
def hotpo(n):
calculator = 0
while n >= 1:
if n % 2 == 0:
n = n / 2
else:
n = 3 * n + 1
calculator = calculator + 1
return calculator
``````

## Solution – 1

you are dividing number by 2 if number is even but multiplying it by 3 and adding 1 into it.

so for any number it will keep doing this
2,1,4,2,1,4,2,1,4,2,1,4,2,1,4,…..

you just have to change condition to `n>1` in while loop

because at last 2 will come and it got divided by 2, then n becomes 1 then again it will consider 1 as odd as per your condition then again 1*3+1=4 and again 4/2=2 and so on…

I hope you understood..

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